The tonicity of the solution in the beaker Environment = Hypertonic solution
1a. Mass of bag before experiment = 15.3 g
Mass of bag after experiment = 12.7 g
Percent change = [(15.3-12.7)/15.3] X 100
= 16.99%
1b. Bag = 5%
Beaker solution = 15%
i.e. the bag is hypotonic to the beaker solution resulting in the exosmosis of water into the beaker.
i.e. Water moves from high water potential to low water potential
Water moves from hypotonic solution to hypertonic solution
2. Cell = 7% solution
Environment = 15% solution
i.e. the cell is hypotonic to the environment resulting in the exosmosis (OSMOSIS) of water into the environment.
Cell = Hypotonic solution
Environment = Hypertonic solution
Complete question: CRITICALTHINKING QUESTIONS
1. A pre-weighed dialysis bag which contalned a solution of [tex]$5 \%$[/tex]glucose was placed in a beaker containing solution of [tex]$15 \% $[/tex]glucose. After one hour, the bag was weighed again.
a. Calculate the [tex]$\%$[/tex]mass change of this dialysis bag from the following information:
- Mass of bag before experimenti 15,3 [tex]$\mathrm{g}$[/tex]
- Mass of bag after experiment: [tex]$12.7 \mathrm{~g}$[/tex]
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