a mixture of helium and hydrogen gases at a total pressure of 698 mm hg contains helium at a partial pressure of 235 mm hg. if the gas mixture contains 0.412 grams of helium, how many grams of hydrogen are present?

Respuesta :

Grams of hydrogen present is =  0.206 gram.

In a mixture of gases, every constituent fuel has a partial strain that is the notional stress of that constituent gasoline as if it by myself occupied the complete quantity of the original aggregate at an equal temperature.

Partial pressure is defined as a box packed with a couple of gasoline, every fuel exerts strain. The stress of all and sundry gas in the container is referred to as its partial strain.

Partial pressure is the factor of total stress associated with a selected fuel species, whilst the whole strain is the sum of partial pressures for all fuel species contributing in a particular location in which the pressure is measured.

given,

Total pressure = 698 mm of Hg

partial pressure of Helium = 235 mm of Hg

mass of helium = 0.412 grams

moles of helium = mass/molar mass

                           = 0.412/4

                           = 0.103 moles.

mass of hydrogen = 0.103 × 2

                          = 0.206 gram

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