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how many milliliters of 3.0m naoh are required to react with 0.5g of cu 2 to form cu(oh)2? ( hint: write the net ionic equation for reaction 2, to get correct mole ratio) ( answer should be written in decimal form)

Respuesta :

rafikiedu08

The number of milliliters of 3.0m NaOH required to react with 0.5g of Cu2+ to form Cu(OH)2 is 5.249 ml

The reaction is as follows;

2NaOH  + Cu2+  ------------> Cu(OH)2  +  2Na+

From the balanced chemical reaction, 0.5 g of Cu2+ = 0.5/63.5 = 7.874x10-3 moles  (molar mass of Cu2+ = 63.5 g)

Thus, moles of NaOH required = 2*moles of Cu2+ = 0.01575

Now, moles of NaOH = molarityxvolume in litres

or,  3*volume in litres = 0.01575

or, volume in litres  = 5.249*10-3 litres = 5.249 ml

  • A balanced chemical equation is one that contains the same number of atoms on either side of the equation.
  • It follows the law of conservation of mass.

To learn more about balanced chemical equation visit:

brainly.com/question/28294176

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