Given the equation
[tex]7(x-5)=2x-10[/tex]First step solve the term in the parenthesis by applying the distributive propperty of mutiplication that states that if you have a(b+c)→ab+ac
[tex]\begin{gathered} 7(x-5)=2x-10 \\ 7x-35=2x-10 \end{gathered}[/tex]Next pass all x-related terms to one side of the equation and the others to the other side:
[tex]\begin{gathered} 7x-35=2x-10 \\ 7x-2x=-10+35 \\ 5x=25 \\ x=\frac{25}{5} \\ x=5 \end{gathered}[/tex]x=5
