We have the following:
When two sides are congruent it is because they are equal
[tex]\begin{gathered} AB=BC \\ 6x+3=8x-1 \end{gathered}[/tex]solving for x:
[tex]\begin{gathered} 6x+3=8x-1 \\ 8x-6x=3+1 \\ 2x=4 \\ x=\frac{4}{2} \\ x=2 \end{gathered}[/tex]replacing:
[tex]\begin{gathered} AB=6\cdot2+3=12+3=15 \\ BC=8\cdot2-1=16-1=15 \\ AC=10\cdot2-10=20-10=10 \end{gathered}[/tex]The answer is:
x = 2
AB =15
BC = 15
AC = 10
