contestada

Let the universal set S have 146 elements A and B are subsets of S set A contains 96 and elements and set B contains 48 elements if sets A ans B have 24 elements in common how many elements are in a but not in b

Respuesta :

Given that:

n(S) = 146, n(A) = 96, n(B) = 48

[tex]n(A\cap B)=24[/tex]

Find

[tex]n(A\cap B^C)[/tex]

[tex]\begin{gathered} n(A\cap B^C)=n(A)-n(A\cap B) \\ =96-24 \\ =72 \end{gathered}[/tex]

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