EXPLANATION
Given the ordered pairs: J(-3,11) and K(1,-3), to calculate the equation of the line we use the following expression:
y= mx + b
First, we need to calculate the slope in this way:
[tex]\text{Slope = }\frac{(y2-y1)}{(x2-x1)}=\frac{(-3-11)}{(1-(-3))}=\frac{(-14)}{(4)}=-\frac{7}{2}[/tex]
With this slope-value we take either one ordered pair and calculate b-value:
[tex]11\text{ = -}\frac{7}{2}(-3)+b[/tex]
Simplifying:
[tex]11\text{ = }\frac{\text{21}}{2}+b[/tex]
Isolating b:
[tex]b\text{ = 11 - }\frac{21}{2}\text{ = }\frac{\text{1}}{2}[/tex]
Then, the equation will be:
[tex]y\text{ = -}\frac{7}{2}x+\frac{1}{2}[/tex]
The standard form will be:
[tex]\frac{7}{2}x+y\text{ = }\frac{1}{2}[/tex]
Multiplying both sides by 2:
[tex]7x+2y\text{ = 1}[/tex]
ANSWER is B) 7x + 2y = 1
