A 1600 gallon pool is being drained. It is being drained at a rate of 50 gallons per hour. I have put everything in the table and graphed it and answered the questions, I just need help with the equation.

The equation representing the real-world scenario is linear as shown io the graph.
Generally, a linear equation takes the form:
[tex]\begin{gathered} y\text{ =mx + c} \\ \text{where m is the slope} \\ c\text{ is the intercept} \end{gathered}[/tex]The slope (m) is calculated using the formula:
[tex]m\text{ = }\frac{y_2-y_1}{x_2-x_1}[/tex]On the line, we have the points: (0, 1600), (4, 1200)
Substituting we have:
[tex]\begin{gathered} m\text{ = }\frac{1200-1600}{4-0} \\ =\text{ }\frac{-400}{4} \\ =\text{ -100} \end{gathered}[/tex]The y-intercept is the value of the y-axis when the line cuts the y-axis
y-intercept : (0, 1600)
Hence, the equation is:
[tex]y\text{ = -100x + 1600}[/tex]