The equation of the line given is:
[tex]8x-10y=-60[/tex]Let's re-arrange it in the slope-intercept form [ y = mx + b ]:
[tex]\begin{gathered} 8x-10y=-60 \\ -10y=-8x-60 \\ y=\frac{-8x}{-10}-\frac{60}{-10} \\ y=\frac{8}{10}x+6 \\ y=\frac{4}{5}x+6 \end{gathered}[/tex]The slope is 4/5 and the y-intercept is 6.
The slope of the line parallel will be the same!!
Thus, the slope of the line parallel is:
[tex]\frac{4}{5}[/tex]