what is the trig for sinC ? this problem is alittle confusing to me

Given a right triangle at B
for the angle C
Opposite side = 27
Hypotenuse = 45
so,
[tex]\sin C=\frac{opposite}{hypotenuse}=\frac{27}{45}=\frac{9\cdot3}{9\cdot5}=\frac{3}{5}[/tex]So, the answer is option B. 3/5