Given data
*The given mass of the lawnmower is m
*The given coefficient of friction is
[tex]\mu[/tex]
*The force exerted by the handle is
[tex]F_h[/tex]
The free-body diagram is given below
The net force acting in the horizontal direction is given as
[tex]\begin{gathered} f-F_h\cos \theta=0 \\ \mu N-F_h\cos \theta=0 \\ \mu N=F_h\cos \theta \end{gathered}[/tex]
The net force acting in the vertical direction is given as
[tex]mg+F_h\sin \theta=N[/tex]
Now, Substitute the values in the horizontal direction of the forces equation as we get
[tex]\begin{gathered} \mu(mg+F_h\sin \theta)=F_h\cos \theta \\ F_h=\frac{\mu mg}{(\cos \theta-\mu\sin \theta)} \end{gathered}[/tex]
