We will solve as follows! :
[tex]p^2+3p-34=6\Rightarrow p^2+3p-40=0[/tex]
Now, we replace in the quadratic formula:
[tex]p=\frac{-(3)\pm\sqrt[]{3^2-4(1)(-40)}}{2(1)}\Rightarrow\begin{cases}p=5 \\ p=-8\end{cases}[/tex]
So, the solutions are p = 5 and p = -8.
