Substituting eqn(2) into eqn(1), we get
[tex]\begin{gathered} 3x-2(5x)=14 \\ 3x-10x=14 \\ -7x=14 \\ \text{Dividing both sides by -7, we get} \\ x=\frac{14}{-7} \\ x=-2 \end{gathered}[/tex]Substituting -2 for x in eqn(2), we get
[tex]y=5x=5(-2)=-10[/tex]Hence, the correct answer is (-2,-10) (option A)