Since ∆JKL and ∆MNO are similar, this means, the ratio of each corresponding sides is equal.
Therefore, we can say that:
[tex]\frac{MN}{JK}=\frac{NO}{KL}[/tex]
Let's plug in the length of MN, JK, and NO in the equation above.
[tex]\frac{2}{3}=\frac{5}{KL}[/tex]
Then, solve for KL.
[tex]\begin{gathered} \text{Cross multiply.} \\ 2KL=15 \\ \text{Divide both sides by 2.} \\ \frac{2KL}{2}=\frac{15}{2} \\ KL=7.5 \end{gathered}[/tex]
Therefore, the length of side KL is 7.5 units.
