Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a diameter of 6 feet and a height of 6 feet. Container B has adiameter of 4 feet and a height of 10 feet. Container A is full of water and the water ispumped into Container B until Conainter B is completely full.After the pumping is complete, what is the volume of the empty space insideContainer A, to the nearest tenth of a cubic foot?

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Answer

[tex]44.0ft^3[/tex]

Explanation

The amount of water in each container shall be calculated using

the volume of a cylinder formula

Note The volume of a cylinder is given by the formula

[tex]V=\pi r^2h\text{ }[/tex]

where r = radius of the cylinder and h = height of the cylinder

For the first cylinder,

diameter d =6 feet,this implies that

radius r = 6/2 = 3 feet

h = 6 feet.

Therefore the volume of the Container A is calculated as thus

[tex]\begin{gathered} V\text{ = 3.14 }\times3^{2\text{ }}\times6 \\ V\text{ = 3.14 }\times\text{ 9 }\times\text{ 6} \\ V=169.56ft^3 \end{gathered}[/tex]

And the volume of the container B as thus

r =4/2 = 2 feet, h = 10 feet

[tex]\begin{gathered} V\text{ = 3.14 }\times2^2\text{ }\times\text{ 10} \\ V\text{ = 3.14 }\times4\text{ }\times\text{ 10} \\ V=125.6ft^3 \end{gathered}[/tex]

After the pumping is complete, the volume of the empty space inside

Container A will be

[tex]\begin{gathered} \text{Volume of container A - Volume of container B} \\ 169.56\text{ - 125.6} \\ 44.0ft^3 \end{gathered}[/tex]