A 1,725 kg car accelerates from 3.0 m/s for 4.4 s and reaches a velocity of 12.0 m/s. Ignoring friction, what is the applied force from the engine?

Respuesta :

Given:

The mass of the car is m = 1725 kg

The initial velocity of the car is

[tex]v_i=\text{ 3 m/s}[/tex]

The final velocity of the car is

[tex]v_f=\text{ 12 m/s}[/tex]

The time is t = 4.4 s

To find the applied force.

Explanation:

The force can be calculated by the formula

[tex]F=\text{ ma}[/tex]

Here, a is the acceleration.

The acceleration can be calculated as

[tex]\begin{gathered} a=\frac{v_f-v_i}{t} \\ =\frac{12-3}{4.4} \\ =2.045\text{ m/s}^2 \end{gathered}[/tex]

On substituting the values, the force applied will be

[tex]\begin{gathered} F=ma \\ =1725\times2.045 \\ =3527.625\text{ N} \end{gathered}[/tex]

Thus, the applied force is 3527.625 N

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