Given
[tex]\begin{gathered} initial\text{ population\lparen a\rparen=2300} \\ r=15.1\text{\%} \\ t=6\text{ years} \end{gathered}[/tex]Explanation
The exponential growth model is given as;
[tex]P(x)=a(1+r)^t[/tex]Therefore, the exponential growth model becomes
[tex]\begin{gathered} p(x)=2300(1+\frac{15.1}{100})^6 \\ =2300(1+0.151)^6 \\ =2300(1.151)^6 \\ =5347.85690 \end{gathered}[/tex]Answer 1: Exponential model
[tex]P(x)=2300(1.151)^x[/tex]Answer 2: The population in 6 years
[tex]5348[/tex]