Answer:
Range = [-9, ∞)
Explanation:
The given equation is:
[tex]y=x^2-2x-8[/tex]
Compare the equation with:
[tex]y=ax^2+bx+c[/tex]
a = 1, b = -2, c = -8
f(-b/2a) is the minimum value of the range (y)
First find -b/2a
-b/2a = -(-2)/2(1)
-b/2a = 2/2
-b/2a = 1
f(-b/2a) = f(1)
[tex]\begin{gathered} f(1)=1^2-2(1)-8 \\ \\ f(1)=1-2-8 \\ \\ f(1)\text{ = -9} \end{gathered}[/tex]
Therefore, the range of the function is all real numbers greater than or equal to -9
Range = [-9, ∞)
