Solution:
The volume of a cylinder is expressed as
[tex]\begin{gathered} volume\text{ = }\pi\times r^2\times h \\ where \\ r\Rightarrow radius\text{ of the circular ends of the circle} \\ h\Rightarrow height\text{ of the cylinder} \end{gathered}[/tex]
Given the cylinder:
Step 1: Evaluate the radius of the circular end of the cylinder.
[tex]\begin{gathered} radius=\frac{diameter}{2} \\ =\frac{4cm}{2} \\ \Rightarrow r=2\text{ cm} \end{gathered}[/tex]
Step 2: Evaluate the volume of the cylinder.
Thus,
[tex]\begin{gathered} volume\text{ = }\pi\times r^2\times h \\ where \\ r=2\text{ cm} \\ h=\text{ 8 cm} \\ thus, \\ volume\text{ = }\pi\times2\text{ }\times2\times8 \\ =100.5309649\text{ } \\ \Rightarrow volume\approx100.5\text{ \lparen nearest tenth\rparen} \end{gathered}[/tex]
Hence, the volume of the cylinder, to the nearest tenth, is
[tex]100.5[/tex]
