The expression given is
[tex]9-2+(9+8\times3)[/tex]To solve the expression above, we will use the sequence of BODMAS
[tex]\begin{gathered} B=\text{bracket} \\ O=of \\ D=\text{divison} \\ M=\text{Multiplication} \\ A=\text{addition } \\ S=\text{substraction} \end{gathered}[/tex]Step 1: we will deal with the expression in the brackets
[tex]\begin{gathered} 9-2+(9+8\times3)\text{ becomes} \\ 9-2+(9+24)\text{ multiplication comes before addition} \end{gathered}[/tex]Step 2: Solve the addition inside the bracket
[tex]\begin{gathered} 9-2+(9+24) \\ 9-2+33 \end{gathered}[/tex]Step 3: solve the expression to have the final answer
[tex]\begin{gathered} 9-2+33 \\ 7+33 \\ =40 \end{gathered}[/tex]Hence,
The final answer = 40
