The situation is represented by a linear form since it has an initial value and a constant rate of change (fee per mile):
Linear situations are represented by the following:
[tex]\begin{gathered} y=mx+b \\ \text{where,} \\ b=\text{initial value} \\ m=\text{constant rate of change} \end{gathered}[/tex]
Then, since Eddie has $15 to spend, he has to spend $15 or less:
[tex]\text{\$1}.75+\text{\$}0.25x\leq\text{\$}15[/tex]
Now, solve for x to determine gow many miles Eddie can travel:
[tex]\begin{gathered} \text{Subtract \$1.75 on each side:} \\ 1.75-1.75+0.25x\leq15-1.75 \\ \text{Divide by 0.25 both sides:} \\ \frac{0.25}{0.25}x\leq\frac{13.25}{0.25} \\ x\leq53 \end{gathered}[/tex]
He can travel 53 miles. The answer would be A.
