Given the following function:
[tex]\text{ y = -x}^2\text{ - 4x - 1}[/tex]
We are tasked to find the y-value of a graph reaching its maximum at x = -2.
We get,
[tex]\text{ y = -x}^2\text{ - 4x - 1}[/tex][tex]\text{ y = -(-2)}^2\text{ - 4(-2) - 1}[/tex][tex]\text{ y = -(4) + 8 - 1}[/tex][tex]\text{ y = -4 + 8 - 1}[/tex][tex]\text{ y = }3[/tex]
Therefore, the y-value is 3.
