Respuesta :

Part A

we can calculate the slope taking two points of the line and using the slope formula

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

where (x2,y2) is a right point from (x1,y1)

i will use the points (8,32) and (12,24)

so replacing

[tex]\begin{gathered} m=\frac{24-32}{12-8} \\ \\ m=\frac{-8}{4}=-2 \end{gathered}[/tex]

the slope is -2

Part B

to make the equation we use the general form of the line

[tex]y=mx+b[/tex]

where m is the slope and b the y-intercept, we have the slope because s is the same line than HI

so m=-2

now replace the slope and a point on the general equation to find b

i will use the point (8,32)

[tex]\begin{gathered} (32)=(-2)(8)+b \\ 32=-16+b \\ b=32+16 \\ b=48 \end{gathered}[/tex]

now we can rewrite the equation replacing b=48 and m=-2

the equation is

[tex]y=-2x+48[/tex]