Hello!
First of all, let's rewrite some square roots and their values:
[tex]\begin{gathered} \sqrt{1}=1 \\ \sqrt{4}=2 \\ \sqrt{9}=3 \\ \sqrt{16}=4 \\ \sqrt{25}=5 \\ \sqrt{36}=6 \end{gathered}[/tex]
Knowing it, let's analyze your problem:
We know that the square root of 36 is 6.
Let's try to rewrite this expression but in another way, also obtaining the same result 6.
Let's do it:
[tex]\begin{gathered} \sqrt{4}\cdot\sqrt{9}=\sqrt{36} \\ 2\cdot3=6 \end{gathered}[/tex]
Answer:
[tex]\sqrt{4}\cdot\sqrt{9}=\sqrt{36}[/tex]
