Two 4.72 kg masses are 3.12 m apart on a frictionless table. Each has 85.5 microCoulombs of charge. What is the initial acceleration of each mass if they are released and allowed to move?

Respuesta :

We are given the following information

Mass of objects: m = 4.72 kg

Distance between objects: r = 3.12 m

Charge: q = 85.5 μC

We are asked to find the initial acceleration of each mass.

Recall from Newton's second law of motion,

[tex]F=m\cdot a[/tex]

Where F is the force between two masses, m is the mass, and a is the acceleration.

First, let us find the force between the two masses.

Recall from Coulomb's law,

[tex]F=\frac{k\cdot q_1\cdot q_2}{r^2}[/tex]

Where k is the Coulomb's law constant that is k = 9×10⁹ Nm²/C²

Substitute the given values into the above formula

[tex]\begin{gathered} F=\frac{9\times10^9\cdot85.5\times10^{-6}\cdot85.5\times10^{-6}}{3.12^2} \\ F=6.7587\;N \end{gathered}[/tex]

Finally, the initial acceleration of each mass is

[tex]\begin{gathered} F=m\cdot a \\ a=\frac{F}{m} \\ a=\frac{6.7587}{4.72} \\ a=1.43\;\frac{m}{s^2} \end{gathered}[/tex]

Therefore, the initial acceleration of each mass is 1.43 m/s^2

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