Statement Problem: Show how to use the unit circle to find tan B.
Solution: Given that triangle ABC has side lengths of;
[tex]a=15inches,b=15\sqrt[]{3}inches,c=30inches[/tex]
Using Unit circle;
The tangent is;
[tex]\begin{gathered} \tan B=\frac{\sin B}{\cos B} \\ \tan B=\frac{15\sqrt[]{3}}{30}\div\frac{15}{30} \end{gathered}[/tex][tex]\begin{gathered} \tan B=\frac{15\sqrt[]{3}}{30}\times\frac{30}{15} \\ \tan B=\sqrt[]{3} \end{gathered}[/tex]
