Given:
The force of attraction is F = 10 N.
Let the mass of each ball is m and the distance between them is r.
To find:
The force of attraction when one of the balls has a mass of 2m and the distance between them is 3r.
Solution:
The force of attraction is given by the formula
[tex]F=\frac{Gmm}{r^2}[/tex]
Here, G is the gravitational constant.
The new force of attraction will be
[tex]\begin{gathered} F^{\prime}=\frac{Gm(2m)}{(3r)^2} \\ =\frac{2}{9}\times\frac{Gmm}{r^2} \\ =\frac{2}{9}F \\ =2.22\text{ N} \end{gathered}[/tex]
Final Answer: The force of attraction when the mass of one of the balls doubled and the distance between them is tripled will be 2.22 N.
