Respuesta :
Given:
In 1960, the population of a town was 13000 people.
Over the course of the next 50 years, the town grew at a rate of 30 people per year.
let t=0 be 1960, and t=1 be 1961
So, the population will increase by a constant number each year.
The equation to find the population will be as follows:
[tex]p=30t+13000[/tex]A) Assuming this continues, what is the population predicted to be in `2040`?
So, t = 2040 - 1960 = 80
Substitute t = 180
[tex]p=30*80+13000=15400[/tex]=================================================================
B) Set up and solve the equation to find in which year the population will reach `16` thousand
Now, we will find the number of years the population will reach 16000
So, substitute p = 16000 then solve for (t)
[tex]\begin{gathered} 30t+13000=16000 \\ 30t=16000-13000 \\ 30t=3000 \\ t=\frac{3000}{30}=100 \end{gathered}[/tex]So, the year will be = 1960 + 100 = 2060
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So, the answer will be:
(A) = 15400 people
(B) 2060
