A square-based pyramid comprises of a square base and 4 triangular faces too
Therefore,
The surface area of a square-based pyramid is calculated as
[tex]\begin{gathered} S\mathrm{}A=\text{Area of square+ area of 4 tiriangular faces} \\ S\mathrm{}A=l^2+4(\frac{1}{2}\times base\times height) \\ \text{where,} \\ l=4.8m \\ \text{base}=4.8m \\ \text{height of the triangle=13.6m} \end{gathered}[/tex]By substitution,
[tex]\begin{gathered} S\mathrm{}A=(4.8m)^2+4(\frac{1}{2}\times4.8m\times13.6m) \\ S\mathrm{}A=23.04m^2+4(\frac{65.28m^2}{2}) \\ S\mathrm{}A=23.04m^2+4(32.64m^2) \\ S\mathrm{}A=23.04m^2+130.56m^2 \\ S\mathrm{}A=153.6m^2 \\ to\text{ the nearest whole number} \\ S\mathrm{}A=154m^2 \end{gathered}[/tex]Hence,
The surface area of the square-based pyramid to the nearest whole number is 154m²
