From the graph the center of the circle is (-1,-2)
The formula for finding the circle with the center is,
[tex](x-a)^2+(y-b)^2=r^2[/tex]
Now, substituting the given points into the above formula we get,
[tex]\begin{gathered} (x+1)^2+(y+2)^2=(\sqrt[]{1^2+2^2}) \\ (x+1)^2+(y+2)^2=5 \end{gathered}[/tex]
So, the required equation of the circle is,
[tex](x+1)^2+(y+2)^2=5[/tex]
