Mr. Gordon and Mr. O want to race their Tesla's from Englewood Stem to Soldier Field. Soldier Field is approximately 10.5 km away. It takes Mr. O 30 minutes to show up to the stadium. Mr. Gordon arrives 30 minutes after Mr. O. How much faster in (Meters/second) is Mr. O's avg. speed for the race? *

Respuesta :

The distance is the same that was covered.

Distance is speed multiplied by time.

Mr O takes 30 minutes and Mr Gordon takes 1 hour.

So the speed of Mr O is given by:

[tex]\text{Speed}=\frac{10.5\operatorname{km}}{1hr}=10.5\operatorname{km}\text{ /hr}[/tex]

Convert the speed in meter per second.

[tex]S_O=10.5\times\frac{5}{18}=\frac{35}{12}m\text{ /s}[/tex]

The speed of mr G is:

[tex]S_G=\frac{10.5}{0.5}=21\operatorname{km}\text{ /hr=}\frac{35}{6}m\text{ /s}[/tex]

So the difference between the speeds is:

[tex]\frac{35}{6}-\frac{35}{12}=\frac{35}{12}=2.9166667\text{ m/s}[/tex]

So Mr O is 2.9167 m/s faster than Mr Gordon.