In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
A = 48π cm²
r = 16 cm
θ = ?
Step 02:
[tex]A\text{ = }\frac{\theta\cdot r^2}{2}[/tex][tex]\begin{gathered} 48\pi=\frac{\theta\cdot16^2}{2} \\ \frac{48\pi\cdot2}{16^2}=\theta \end{gathered}[/tex][tex]\frac{96\pi}{256}=\theta[/tex][tex]\frac{3\pi}{8}=\theta[/tex]
The answer is:
θ = 3 π / 8
