A ladder leans against a building, making a 63 angle of elevation with the ground.The top of the ladder reaches a point on the building that is 37 feet above theground. To the nearest tenth of a foot, what is the distance between the base of the building and the base of the ladder? Use the correct abbreviation for the units.If the answer does not have a tenths place then include a zero so that it does.

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Solution

- To better understand the problem, we can make a sketch as follows:

- The above figure depicts what was described by the question.

- We are asked to find the distance between the base of the ladder and the base of the building, and we have labeled it as x.

- To find the value of x, we simply apply SOHCAHTOA.

- That is,

[tex]\begin{gathered} \tan\theta=\frac{Opposite}{Adjacent} \\ \\ \tan63\degree=\frac{37}{x} \\ \\ \text{ Rewrite,} \\ \\ x=\frac{37}{\tan63\degree} \\ \\ \therefore x=18.852441...\approx18.9\text{ \lparen TO THE NEAREST TENTH OF A FOOT\rparen} \end{gathered}[/tex]

Final Answer

The distance of the base of the building from the base of the ladder is 18.9 feet.

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