The rocks are distributed evenly on the land.
Therefore,
[tex]\begin{gathered} 1\text{ acre=43,56}0\text{ sq f}eet \\ 10\text{ acres =?} \\ \text{cross multiply} \\ \text{area in square f}eet=43560\times10=435600\text{ square f}eets \end{gathered}[/tex][tex]\begin{gathered} \text{ 360 square f}eet=10\text{ rocks } \\ 435600\text{ square fe}et=? \\ \text{amount of rocks = }\frac{435600\times10}{360}=12100\text{ rocks} \end{gathered}[/tex]12100 rocka are on 10 acres of land
