The manufacturer's price for a cooler is $28.50 A camping store that buys the coolers sells them for $40.76 What is the approximate percent of increase in the price of the coolers?.... might have to zoom in

The percent of the increase is
[tex]I=\frac{N-O}{O}\times100[/tex]I is the increasing value
N is the new value
O is the original value
The price of the cooler is $28.50, then
O = 28.50
The selling price of the cooler is $40.76, then
N = 40.76
We will substitute them in the rule above to find I
[tex]I=\frac{40.76-28.50}{28.50}\times100[/tex]Let us calculate it
I = 43.0175 %
Round it to the nearest percent
I = 43%
The answer is D