The equation:
[tex]x^2-6x-7=0[/tex]
can be factor as follows:
[tex](x-7)(x+1)=0[/tex]
this implies that:
[tex]\begin{gathered} x-7=0 \\ x=7 \\ \text{or} \\ x+1=0 \\ x=-1 \end{gathered}[/tex]
Therefore the solutions to the equation are 7 and -1; and the asnwer is the last option.
