Answer:
3.6 Units
Explanation:
Given points X(4, 2) and Y(7,4), to determine the distance between X and Y we use the distance formula below:
[tex]\text{Distance}=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex][tex]\begin{gathered} \text{Point X(4,2) }\implies x_1=4,y_1=2 \\ \text{Point Y(7,4) }\implies x_2=7,y_2=4 \end{gathered}[/tex]Substituting these points into the distance formula, we have:
[tex]\begin{gathered} \text{XY}=\sqrt{(7-4)^2+(4-2)^2} \\ =\sqrt{3^2+2^2} \\ =\sqrt{9+4} \\ =\sqrt{13} \\ =3.6\text{ Units (correct to the nearest tenth)} \end{gathered}[/tex]The distance between X and Y is 3.6 Units.
