Given,
The supply voltage, V=122 V
The current drawn by the oven, I=6 A
From Ohm's law, the voltage across a load is proportional to the current through the load.
Thus the supply voltage of the oven is given by,
[tex]V=IR[/tex]Where R is the resistance of the oven.
On rearranging the above equation,
[tex]R=\frac{V}{I}[/tex]On substituting the known values,
[tex]\begin{gathered} R=\frac{122}{6} \\ =20.33\text{ }\Omega \end{gathered}[/tex]Thus the resistance of the oven when it is fully heated is 20.33 Ω
