EXPLANATION
Let's see the facts:
Race = 100-yard
Toko--> 10 yards < Yolanda
Second part:
Yolanda --> 10 yards behind the starting line
If each geil ran at the same speed as the first race, the appropiate relationship is as follows:
Yolanda's speed = 100 yards/race
Yoko's speed = 90 yards/race
Distance= ratex time
For the second race, Yolanda ran 110 yards at the same speed --> So it will take 110/100 = 1.1 times to finish the race.
Yoko runs 100 yards at the same speed so it will take her 100/90= 1.11111... times to finish the run.
As 1.11 is less time than 1.1111, Yolanda will win the race.
b) In order to finish in a tie, the times must be the same.
Let x be the head start given to Yoko so that they tie.
time = distance / rate
[tex]\frac{100+x}{100}=\frac{100}{90}[/tex]
Multiplying both sides by 100:
[tex]100+x=100\cdot\frac{100}{90}[/tex]
Subtracting -100 to both sides:
[tex]x=100\cdot\frac{100}{90}-100[/tex]
Simplifying:
[tex]x=111.11111\ldots-100=11.111\ldots[/tex]
So, if Yoko has 11.111... head start, they should tie on the next race.
