Find the coordinates of the center, vertices, covertices, foci, length of transverse and cojugate axis and the equation of the asymptotes. Then graph the parabola.

The given equation is:
[tex]\frac{x^2}{9}-\frac{y^2}{49}=1[/tex]The equation matches the general equation of a hyperbola given by:
[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]Hence a=3 and b=7.
The center is at origin (0,0)
The vertices are at (3,0) and (-3,0)
The focii are:
[tex](\sqrt[]{58},0),(-\sqrt[]{58},0)[/tex]The equation of the asymptotes are:
[tex]y=\frac{7x}{3},y=-\frac{7x}{3}[/tex]There are no covertices since the hyperbola does not have covertices.
The graph is given below: