Find the coordinates of the center, vertices, covertices, foci, length of transverse and cojugate axis and the equation of the asymptotes. Then graph the parabola.

Find the coordinates of the center vertices covertices foci length of transverse and cojugate axis and the equation of the asymptotes Then graph the parabola class=

Respuesta :

The given equation is:

[tex]\frac{x^2}{9}-\frac{y^2}{49}=1[/tex]

The equation matches the general equation of a hyperbola given by:

[tex]\frac{x^2}{a^2}-\frac{y^2}{b^2}=1[/tex]

Hence a=3 and b=7.

The center is at origin (0,0)

The vertices are at (3,0) and (-3,0)

The focii are:

[tex](\sqrt[]{58},0),(-\sqrt[]{58},0)[/tex]

The equation of the asymptotes are:

[tex]y=\frac{7x}{3},y=-\frac{7x}{3}[/tex]

There are no covertices since the hyperbola does not have covertices.

The graph is given below:

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