The middle of the landing track passes through the points (8, -3) and (10, -2).
The slope of a line that passes through points (x1, y1) and (x2, y2) is computed as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Replacing with the points (8, -3) and (10, -2),
[tex]m=\frac{-2-(-3)}{10-8}=\frac{1}{2}[/tex]
The slope-intercept form of a line is:
y = mx + b
where m is the slope and b is the y-intercept. Replacing with m = 1/2 and point (8, -3), we get:
-3 = 1/2(8) + b
-3 = 4 + b
-3 - 4 = b
-7 = b
Then, the equation is:
y = 1/2x - 7
