[tex]-8\text{ and -6}[/tex]
Explanation
Step 1
Let x represent the first number
as the numbers are consecutive even integers, the next number would be x+2
so, the numbers are
[tex]x,\text{ and x+2}[/tex]
Also,we have
a)Tripling the greater of two consecutive even integers gives the same result as subtracting 10 from the lesser even integer, so
[tex]3(x+2)=x-10[/tex]
Step 2
solve the equation
[tex]\begin{gathered} 3(x+2)=x-10 \\ \text{apply distributive property} \\ 3x+6=x-10 \\ \text{subtract x in both sides} \\ 3x+6-x=x-10-x \\ 2x+6=-10 \\ \text{subtract 6 in both sides} \\ 2x+6-6=-10-6 \\ 2x=-16 \\ \text{divide both sides by 2} \\ \frac{2x}{2}=\frac{-16}{2} \\ x=-8 \end{gathered}[/tex]
so, the numbers are
[tex]\begin{gathered} x=-8 \\ x+2=-8+2=-6 \end{gathered}[/tex][tex]-8\text{ and -6}[/tex]
I hope this helps you
