ANSWER
A = 62 degrees
EXPLANATION
Given:
A triangle with side a = 14 m, b = 12m and angle B = 49 degrees.
Result:
Angle A
Using sine rule
[tex]\begin{gathered} \frac{sinA}{a}=\frac{sinB}{b} \\ \end{gathered}[/tex][tex]\begin{gathered} sinA=\frac{asinB}{b} \\ sinA=\frac{14sin49}{12} \\ sinA=\frac{14\times0.7548}{12} \\ sinA=0.8805 \\ A=\sin^{-1}0.8805 \\ A=61.7^0 \end{gathered}[/tex]Hence,
