Given:
The distance traveled by 2 buses is 720 miles.
Let x mi/h be the speed of one bus and (x+16) mi/h be the speed of the other bus.
The distance is given as,
[tex]\begin{gathered} d=rt \\ r=\text{ spe}ed\text{ } \\ t=\text{ time} \end{gathered}[/tex]
The total distance is,
[tex]\begin{gathered} d_1+d_2=720 \\ d_1=5x \\ d_2=5(x+16) \\ 5x+5(x+16)=720 \\ 5x+5x+80=720 \\ 10x=640 \\ x=64 \end{gathered}[/tex]
It gives,
[tex](x+16)=(64+16)=80[/tex]
Answer: the rate of one ( slower) bus is 64 mi/h and another( faster) bus is 80 mi/h.
