Respuesta :

Given the expression

[tex]y^3-4y^2-8y+32[/tex]

Take outside the square of y from the first two terms and -8 and from the last two terms.

[tex]y^2(y-4)-8(y-4)[/tex]

The term y-4 is common. So, take it outside.

[tex](y^2-8)(y-4)[/tex]

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