Solution:
Given:
[tex]2(10-a^2)+7a[/tex]when a = 4, substitute for a in the expression;
[tex]\begin{gathered} 2(10-a^2)+7a=2(10-4^2)+7(4) \\ =2(10-16)+28 \\ =2(-6)+28 \\ =-12+28 \\ =16 \end{gathered}[/tex]Therefore, if (a = 4), then
[tex]2(10-a^2)+7a=16[/tex]
Hence, the answer is 16.
