This situation follows the next exponential decay formula:
[tex]y=a(1+r)^t[/tex]where
• a is the initial hairs
,• r is the losing rate (as a decimal)
,• t is time in years
,• y is the remaining hairs
Replacing with a = 1889, r = -0.26 (notice the negative sign) and t = 8, we get:
[tex]\begin{gathered} y=1889(1-0.26)^8 \\ y=1889(0.74)^8 \\ y\approx170 \end{gathered}[/tex]He will have left about 170 hairs after 8 years
