Roy used a compass and a straightedge to construct DEF so that it would be congruent to LABC.BCEWhich statement about the angle segments is not true?A BAEDBBAEFC AC = DFAC = BCA student used a construction to create the diagram below.

1. Being the angles congruent we have that:
[tex]BC=BA=EF=ED[/tex]And
[tex]AC=DF[/tex]Therefore:
[tex]\begin{gathered} BA=ED \\ BA=EF \\ AC=DF \\ AC\ne BC \end{gathered}[/tex]Answer: D