Answer:
[tex][OH^-]\text{ = }1\text{ }\times\text{ 10}^{-5}[/tex]
Explanation:
Here, we want to calculate the concentration of the hydroxide ions
Mathematically:
[tex][H^+]\text{ \lbrack OH}^-]\text{ = 10}^{-14}[/tex]
We now proceed to substitute the value of [H+]
We have that as follows:
[tex]\begin{gathered} 10^{-9}\text{ }\times\text{ \lbrack OH}^-]\text{ = 10}^{-14} \\ [OH^-]\text{ = }\frac{10^{-14}}{10^{-9}}\text{ = 10}^{-5} \end{gathered}[/tex]
