[tex]x=-38,y=5.2[/tex]
1) Let's graph this system. The first thing to do is to set a t-table for the first equation, as well as another one to the second.
x|y=-0.2x-2.4
-1 | y= -0.2(-1)-2.4 =-2.2
0| -2.4
1|-2.6
2|-2.8
So the we have these points to plot the first equation: (-1, -2.2), (0,-2.4), (-1,-2.6) and (2,-2.8). Notice that we pick random values for x, and then plugged them into the equation to get the y-values
y=0.6x +28
x|y
-1| 27.4
0|28
1|28.6
2|29.2
Similarly, we did the same. So we have the points (-1, 27.4), (0,28), (1,28.6) and (2,29.2)
2) So this is our system of Linear Equations:
The solution of this system is the common point both lines share (-38.5.2)
